What is an equation of a circle with center (5,0) that passes through the point (1,1)

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23-04-2018
Mathematics

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What is an equation of a circle with center (5,0) that passes through the point (1,1)

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sqdancefan sqdancefan · Answer 1 · 2018-04-23T21:39:33+02:00

sqdancefan sqdancefan

23-04-2018

The equation of a circle with center (h, k) and radius r is
(x -h)² +(y -k)² = r²

This will be true for the given point, allowing us to find r².
(1 -5)² +(1 -0)² = r² = 17

The desired equation is ...
(x -5)² +y² = 17

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Sophiasana Sophiasana · Answer 2 · 2018-04-23T22:00:52+02:00

Sophiasana Sophiasana

23-04-2018

(x-5)2+y2=17
(5,0)=(h,k)
(1,1) =(x,y)
r2=17

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