ijohnh14
ijohnh14
23-04-2018
Mathematics
contestada
someone please answer this please, ASAP!
Respuesta :
Аноним
Аноним
23-04-2018
[tex] \dfrac{-40x^3-12x^2+16x}{-4x} = \dfrac{-4x(10x^2 + 3x - 4)}{-4x} = 10x^2 + 3x - 4[/tex]
Answer: Option A
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meowymeowylee
meowymeowylee
23-04-2018
Hi there!
We could solve the equation by dividing each numerator.
We subtract the exponent when we divide x.
ex) 10x³/2x = 5x² because 3-1=2.
Divide -40x³ by -4x first : 10x²
Then divide -12x by -4x : 3x
Lastly divide 16x by -4x : -4
We can add all of them together.
10x² + 3x - 4
So your answer is 1. 10x² + 3x - 4.
Hope this helped :)
Answer Link
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