Respuesta :

[tex]\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\ ---------\\ a=8.6\\ b=12.9\\ h=6.4 \end{cases}\implies A=\cfrac{6.4(8.6+12.9)}{2} \\\\\\ A=\cfrac{6.4(21.5)}{2}[/tex]