1. You con solve the quadratic equation x^2+20x+100=50 by following the proccedure below:
2. Pass the number 50 from the right member to the left member. Then you obtain:
x^2+20x+100-50=0
x^2+20x+50=0
3. Then, you must apply the quadratic equation, which is:
x=(-b±√(b^2-4ac))/2a
x^2+20x+50=0
a=1
b=20
c=50
4. Therefore, when you simplify, the result is:
-10±5√2 (It is the last option).
