christinanwilli
christinanwilli
24-02-2018
Mathematics
contestada
(x^2+3y-3) - (-2x^2+3y-1)
Respuesta :
creeds25
creeds25
24-02-2018
[tex](x^2+3y-3) - (-2x^2+3y-1) [/tex]
Apply plus/minus rule.
-(-a)=a amd -(a)=-a
[tex](x^2+3y-3) - (-2x^2+3y-1)=x^2+3y-3+2x^2-3y+1 [/tex]
[tex]=x^2+3y-3+2x^2-3y+1 \\ Add \ like \ terms \\ =3x^2 - 2 \\[/tex]
[tex]Answer: \ 3x^2-2[/tex]
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