sandiredd sandiredd

22-07-2014
Mathematics

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what is the equation of a parabola whose vertex is (-4,7) and whose graph is 1/2 as wide as y=x^2

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Аноним Аноним

22-07-2014

[tex]The\ vertex\ form:y=a(x-h)^2+k\\\\vertex\ (h;\ k)\to(-4;\ 7)\\\\then:y=a[x-(-4)]^2+7=a(x+4)^2+7\\\\graph\ is\ half\ as\ wide\ as\ y=x^2\ then\ a=2\\\\Answer:y=2(x+4)^2+7\\\\y=2(x^2+8x+16)+7=2x^2+16x+39[/tex]

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