[tex]\bf \cfrac{x-5}{-2}=\cfrac{x-1}{-3}\implies \cfrac{5-x}{2}=\cfrac{1-x}{3}\impliedby
\begin{array}{llll}
\textit{let's multiply both sides}\\
\textit{by the LCD of 6, to do}\\
\textit{away with the denominators}
\end{array}
\\\\\\
6\left( \cfrac{5-x}{2} \right)=6\left( \cfrac{1-x}{3} \right)\implies 3(5-x)=2(1-x)
\\\\\\
15-3x=2-2x\implies 13=x[/tex]
