iamthepantaloon1698 iamthepantaloon1698
  • 21-12-2017
  • Mathematics
contestada

Find two numbers differing by 36 whose product is as small as possible. enter your two numbers as a comma separated list,
e.g. 2, 3. the two numbers are .

Respuesta :

lesliekolleroxrkcf
lesliekolleroxrkcf lesliekolleroxrkcf
  • 21-12-2017
f(x)=x(x-36)=x²-36x

f'(x) = 2x-36 =0. implies x = 18

answer is 18 and -18
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fichoh
fichoh fichoh
  • 03-11-2021

The two numbers whose which differs by 36 and gives a minimum value for the product is - 18 and 18

Let the first number = a

The second number = a + 36

Product of the two numbers :

a(a + 36)

a² + 36a

At the minimum point ; da/dx = 0

dy/dx= 2a + 36

2a + 36 = 0

2a = - 36

a = - 36 / 2

a = - 18

Hence,

a + 36

-18 + 36 = 18

Therefore, the two numbers are - 18 and 18

Learn more : https://brainly.com/question/25180086

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