BobBball9599 BobBball9599

25-11-2017
Chemistry

contestada

If a buffer solution is 0.190 m in a weak acid (ka = 8.2 × 10-5) and 0.590 m in its conjugate base, what is the ph?\

Respuesta :

07-12-2017

You use the Henderson - Hasselbalch equation pH = pKa + log ([salt]/[acid]) pKa = -log (8.2*10^-5) = 4.081 pH = 4.081 + (0.590/0.190) pH = 4.081 + log 3.105 pH = 4.081 + 0.49206 pH = 4.573

Answer Link

Otras preguntas

I need to find the zeros of the function:f(x)=2x^2-5x-3

Multiply and simplify(x-3y) (x + 3y)

how did hitler change the lives of workers

I need 10 facts about John Williams

What is the function of the pituitary gland?

Represent 23/-4 on number line

How to solve 12^r=13 in solving exponential equation with logarithms

Multiply and simplify(x-3y) (x + 3y)

The recommended dose of Vancocin® for a severe staphylococcal infection is 40 mg/kg/day. The adult weighs 180 pounds and is to receive the medication IV q6h

In the stomach,a. liquids are absorbedb. bile acids dissolve the fats in foodc. food is converted to chymed. nutrients are absorbed through capillaries