brianluong00
brianluong00
24-11-2017
Mathematics
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QUESTION 14 R
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WojtekR
WojtekR
24-11-2017
[tex]|\overrightarrow{WX}|=\sqrt{(6-6)^2+(3-(-3))^2+(4-6)^2}=\sqrt{0^2+6^2+(-2)^2}=\\\\=\sqrt{0+36+4}=\sqrt{40}=\sqrt{4\cdot10}=\sqrt{4}\cdot\sqrt{10}=\boxed{2\sqrt{10}}[/tex]
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