Moles of aluminum carbonate = Mass / Molar mass
= 47.6 g / 233.99 g molâ’1
=0.203 mol
To find moles of oxygen:
In each mole of the carbonate there are 9 moles of oxygen
And thus there are 9 Ă— 0.203 moles of oxygen in the given quantity.
= 1.83 moles of oxygen
Within one mole of oxygen, we have 6.022 x 10^23 atoms
Amount of atoms within 1.827 moles of oxygen = 1.83 x 6.022 x 10^23
= 1.10 x 10^24 atoms
