Respuesta :

[tex]4\frac{3}{4}-\frac{5}{8}\\\\\frac{(4*4)+3}{4}-\frac{5}{8}\\\\\frac{19}{4}-\frac{5}{8}\\\\\frac{19}{4}(\frac{2}{2})-\frac{5}{8}\\\\\frac{38}{8}-\frac{5}{8}\\\\\frac{38-5}{8}\\\\\frac{33}{8}\\\\\\4\frac{1}{8}[/tex]