2+3i
------ should be multiplied (numerator and denominator both) by 2+i. This will
2-i remove i from the denominator.
(2+3i) 2+i 4 + 2i + 6i - 3 1 + 8i
-------- * ----------- = ---------------------- = ---------- (answer)
2-i 2+i 4+(-1) 8
You could also write this as (1/8) + i.
