Given the system of equations Equation 1: x+2y−z=−7 Equation 2: 2x+3y+2z=−3 Equation 3: x−2y−2z=3 Eliminate z using equations 1 and 2. Type the resulting equation below.(Do not use spaces) Question 2 Eliminate z again using equations 2 and 3. Type the resulting equation below. (Do not use spaces) $ Question 3 Using the two new equations you found, eliminate y. Type the resulting equation below. (Do not use spaces) Question 4 What is the value of x? x= Question 5 Substitute this value into one of your equations with only x and y. What is the value of y? y= Question 6 Substitute x and y into one of the original equations. What is the value of z? z=

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greentoowon greentoowon · Answer 1 · 2024-04-20T19:23:20+02:00

Eliminate z using equations 1 and 2: 4x + 7y = -17

Eliminate z again using equations 2 and 3: 6x + 7y = 3

Using the two new equations, eliminate y: 6x = 20

x = 20/6 = 10/3

Substitute x into one of the equations with only x and y:

4(10/3) + 7y = -17

40/3 + 7y = -17

7y = -17 - 40/3

7y = -51/3 - 40/3

7y = -91/3

y = -91/21

Substitute x and y into one of the original equations:

10/3 + 2(-91/21) - z = -7

10/3 - 182/21 - z = -7

70/21 - 182/21 - z = -7

-112/21 - z = -7

z = -7 + 112/21

z = -7 + 16/3

z = -21/3 + 16/3

z = -5/3