Answer:
The point-slope form of a linear equation is \(y - y_1 = m(x - x_1)\), where \((x_1, y_1)\) is a point on the line, and \(m\) is the slope.
In your equation, \(y - 2 = 4(x - 3)\), the point \((3, 2)\) is on the line, and the slope is 4.
Now, you can write the equation in slope-intercept form (\(y = mx + b\)) by simplifying the given equation:
\[y - 2 = 4(x - 3)\]
Distribute the 4:
\[y - 2 = 4x - 12\]
Add 2 to both sides:
\[y = 4x - 10\]
So, the linear function representing the line is \(y = 4x - 10\).
