How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution.

A. 11 L

B. 15 L

C. 25 L

Respuesta :

The answer is B

15 L of pure water must be mixed with 10 L of a 25% acid solution to reduce it to a 10% acid solution

Answer:


Step-by-step explanation:

The answer is B hope this helps!