Relax

Respuesta :

the perpendicular bisectors of the 3 sides will meet at the centre of the circle.

midpoint of EF will be (4+4)2 , (4+2)/2  = (4,3)

equation of EF is  x = 4 so the equation of the line perpendicular to EF will be 
y = 3

midpoint of FG is (6,2)  so line perpendicualr to it is x = 6

so center of the circle is ( 6 , 3)


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