pepetheskunkcat
pepetheskunkcat pepetheskunkcat
  • 24-05-2017
  • Mathematics
contestada

Solve for x.
(x+8)^2=x^2+4x+16

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Аноним Аноним
  • 24-05-2017
expanding the left side:-

x^2 + 16x + 64 = x^2 + 4x + 16 
x^2 - x^2 +16x - 4x + 64 - 16 = 0
12x + 48 = 0
12 x = -48
x = -4

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juanny1818
juanny1818 juanny1818
  • 24-05-2017
(x+8)^2=x^2+4x+16  Simplify both sides of the equation.  x^2+16x+64=x^2+4x+16  Subtract x^2 from both sides.  x^2+16x+64−x^2=x^2+4x+16−x^2  16x+64=4x+16  Subtract 4x from both sides. 16x+64−4x=4x+16−4x 12x+64=16  Subtract 64 from both sides. 12x+64−64=16−64 12x=−48  Divide both sides by 12.‌  12x/12‌=‌−48/12‌  x=−4 Answer:x=−4
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