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irspow
The distance between two points if found using the Pythagorean Theorem...

d^2=(dx)^2+(dy)^2

d^2=(2-0)^2+(3--1)^2

d^2=2^2+4^2

d^2=4+16

d^2=20

d=√20 units

d≈4.47 units (to nearest hundredth of a unit)
whyareyounotgay0
[tex] \sqrt{(2-0) ^{2} + (3-(-1)){2} [/tex] =4.47