The energy released when a certain amount of a substance condenses to a liquid is given by:
[tex]Q=m \lambda_v[/tex]
where m is the mass of the substance and [tex]\lambda_v[/tex] is the latent heat of vaporization.
In this problem, the mass is m=0.06 kg, while the latent heat of vaporization of mercury is [tex]\lambda_v=296 kJ/ kg[/tex]. Therefore, if we apply the formula we get:
[tex]Q=(0.06 kg)(296 kJ/ kg)=17.76 kJ=17760 J[/tex]
So, the correct answer is
C. 17,705.1 J
