Mass Molar of [tex] Ca_{3} (PO_4)_2[/tex]
Ca = 3*40 = 120 amu
P = 2*31= 62 amu
O = (16*4)*2 = 64*2 = 128 amu
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Mass Molar of [tex] Ca_{3} (PO_4)_2[/tex] = 120 + 62 + 128 = 310 g/mol
Therefore: What is the gram formula mass of Ca3(PO4)2 ?
Answer: 310 grams
