For this problem we have the following inequality given:
[tex]-68<8x-4<-36[/tex]
If we want to solve for x the first step on this case would be add 4 in all the sides of the inequality and we got:
[tex]-64<8x<-32[/tex]
Now we can divide all the sides by 8 and we got:
[tex]-\frac{64}{8}<\frac{8x}{8}<-\frac{32}{8}[/tex]
And the solution for this case would be:
[tex]-8
