[tex]\begin{gathered} f(x)=\frac{3}{4}\times(x-2)\times(x+2) \\ =\frac{3}{4}\times(x^2-2^2) \\ =\frac{3}{4}\times(x^2-4) \\ =\frac{3}{4}\times x^2-4\times\frac{3}{4} \\ f(x)=\frac{3x^2}{4}-3 \end{gathered}[/tex]
Thus, the standard form of the given function is,
[tex]f(x)=\frac{3x^2}{4}-3[/tex]
