Let
[tex]y=-\frac{3}{x+1}+2[/tex]
Find the equation in terms of y in the form x = f(y).
[tex]\begin{gathered} y-2=\frac{-3}{x+1} \\ x+1=\frac{-3}{y-2} \\ x=\frac{-3}{y-2}-1 \end{gathered}[/tex]
Replace y by x in the right hand side, which will be the required inverse of the function.
[tex]g^{-1}(x)=-\frac{3}{x-2}-1[/tex]
