Given the roots of the polynomial below,
[tex]-3,0,8[/tex]
with degree 3 and the leading coefficient of 1.
Therefore,
[tex]f(x)=x(x-(-3))(x-8)[/tex]
Let us now expand the above function
[tex]\begin{gathered} f(x)=x(x+3)(x-8) \\ f(x)=x(x(x-8)+3(x-8)) \\ f(x)=x(x^2-8x+3x-24) \\ f(x)=x(x^2-5x-24) \\ f(x)=x^3-5x^2-24x \end{gathered}[/tex]
Hence, the polynomial is
[tex]f(x)=x^3-5x^2-24[/tex]
