Explanation
2 FeCl3 + SnF2 => 2 FeF2 + SnCl4
The half-reaction: oxidation
[tex]\text{ Sn}^{+2}=>\text{ 2e}^{-1}+\text{ Sn}^{+4}[/tex]The half-reaction: reduction
[tex]2\text{ Fe}^{+3}+\text{ 2e}^{-1}=>\text{ 2Fe}^{+2}[/tex]Answer: Sn is oxidized and Fe is reduced
