• According to the balanced equation, we have :
4 Fe(s) + 3 O2(g) → 2 Fe2O3(s)
4 x 55.85g of Fe reacts with 3 x 32g of Oxygen
Given 17.86 g of Ion, we want to find out how much oxygen will be required in this instance .
• So :
M.mass Fe: 4* 55.85 = 223.4
M.mass O2 : 3* 32 = 96
we can rearrange by :
223.4 → 96
17.86 → x .....(cross multiply )
223.4x = 96* 17.86
x = (96 *17.86) / 234.4
x = 7.314
• Therefore mass of oxygen required = 7.3g ,
