DavieonG196514 DavieonG196514

25-10-2022
Mathematics

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solve [tex] \frac{1}{2} (20 - 4a)6 - a[/tex]between 4a) and 6 is suppost to be a = like 4a)=6

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LansonJ462523 LansonJ462523

25-10-2022

[tex]\frac{1}{4}(20-4a)=6-a[/tex][tex]\begin{gathered} 5-a=6-a \\ 5-a=6-a \\ -a+a=6-5 \\ 0=1 \end{gathered}[/tex]

That is inconsistent, therefore there is no solution

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