Multiplication:
[tex]\frac{f(x)}{g(x)}\cdot\frac{h(x)}{j(x)}=\frac{f(x)h(x)}{g(x)j(x)}[/tex]
For the given functions:
[tex]\begin{gathered} \frac{x}{x-7}\cdot\frac{x-2}{x-3}=\frac{x(x-2)}{(x-7)(x-3)} \\ \end{gathered}[/tex]
The expression cannot be simplified and is already written in factored form.
The exclude values are those that make the denominator be equal to zero: 7,3
[tex]\begin{gathered} (x-7)(x-3)=0 \\ \\ x-7=0 \\ z=7 \\ \\ x-3=0 \\ x=3 \end{gathered}[/tex]
