Recall the formula for the Volume of a cone of radius R and height H:
[tex]\text{Volume}=\frac{1}{3}\pi\cdot R^2\cdot H[/tex]Therefore in our case we replace the raduis R with half of the base's diameter: 11/2 = 5.5 cm, and H with the coné height 16 cm, and obtain:
[tex]\text{Volume}=\frac{1}{3}\pi\cdot(5.5)^2\cdot(16)=506.58666\ldots[/tex]The answer is in cm^3, and we are asked to round it to the nearest tenth, so we type:
506.6 cm^3
