NaliyaU565546 NaliyaU565546
  • 25-10-2022
  • Mathematics
contestada

a= 8 in, b= ? C= 14 in.using pythagorean theorem

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TalasiaE706606 TalasiaE706606
  • 25-10-2022

by Pythagorean theorem'

[tex]8^2+b^2=14^2[/tex][tex]\begin{gathered} 64+b^2=196 \\ b^2=196-64 \end{gathered}[/tex][tex]\begin{gathered} b^2=132 \\ b=\sqrt[]{132} \\ b=11.48 \end{gathered}[/tex]

b = 11.48

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