Respuesta :

I will ask my question here

is p(x)

[tex]\begin{gathered} p(x)=-4x^3-6x^2+16x+24 \\ \lim _{x\to\infty}-4x^3-6x^2+16x+24=\lim _{x\to\infty}-4x^3=-4\lim ^{}_{x\to\infty}x^3=-4\infty=-\infty \\ \\ \end{gathered}[/tex]

bye :)

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