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A reaction produces 156 mL of carbon dioxide gas collected
over water at a temperature of 25.0 °C and a pressure of 99.81
kPa. Calculate the volume of CO2 at STP.
mL
Your answer should be rounded to three significant figures. Do not include units
In your answer.

Respuesta :

Eduard22sly

The volume of the CO₂ produced at STP, given the data is 141 mL

Combined gas equation

P₁V₁ / T₁ = P₂V₂ / T₂

Where

  • Initial pressure => P₁
  • Initial temperature => T₁
  • Initial volume => V₁
  • New pressure => P₂
  • New temperature => T₂
  • New Volume => V₂

Data obtained from the question

  • Initial volume (V₁) = 156 mL
  • Initial temperature (T₁) = 25.0 °C = 25 + 273 = 298 K
  • Initial pressure (P₁) = 99.81 KPa
  • New pressure (P₂) = STP = 101.325 KPa
  • New temperature (T₂) = STP = 273 K
  • New volume (V₂) =?

How to determine the volume at P

P₁V₁ / T₁ = P₂V₂ / T₂

(99.81 × 156) / 298 = (101.325 × V₂) / 273

Cross multiply

298 × 101.325 × V₂ = 99.81 × 156 × 273

Divide both sides by 298 × 101.325

V₂ = (99.81 × 156 × 273) / (298 × 101.325)

V₂ = 141 mL

Thus, the volume of the CO₂ produced at STP is 141 mL

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