Answer:
[tex]\sf 2^{(n+1)}[/tex]
Step-by-step explanation:
Explicit formula is used to represent all the terms of the geometric sequence using a single formula.
[tex]\sf \boxed{\bf t_n=ar^{(n-1)}}[/tex]
Here, a is the first term.
r is the common ratio.
r = second term ÷ first term
4, 8,16,32,64,.....
a = 4
r = 8 ÷4 = 2
[tex]\sf t_n =4*2^{(n-1)}[/tex]
[tex]\sf = 4*2^n * 2^{(-1)}\\\\ = 4*2^n*\dfrac{1}{2}\\\\ = 2*2^n[/tex]
[tex]\sf = 2^{(n+1)}[/tex]
