Respuesta :

Sidharth999
Answer: No Solutions

Step-by-Step Explanation:

=> 10x + 2y = 2 (Eq. 1)
=> -5x = y + 10 (Eq. 2)

From Eq. 2 :-

-5x = y + 10
=> x = (y + 10)/-5 (Eq. 3)

Substitute value of ‘x’ from Eq. 3 in 1 :-

10x + 2y = 2
10(y + 10/-5) + 2y = 2
-2(y + 10) + 2y = 2
-2y - 20 + 2y = 10
0 = 10 + 20
=> 0 = 30
LHS is not Equal to RHS.

This is a False Statement and hence this System of Equations has No Solutions.


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