the sum of the digits of a two digit number is 10. if the digits are reversed, the new number will be 18 more than the original number. find the number
1st; t+u=10 2nd: t-u=6 Add 1st and 2nd and solve for t,as follows: 2t = 16 t = 8 Substitute in t+u=10 to solve for u: 8+u=10 u = 2 Original Number = 82
