omarlamd omarlamd

25-01-2022
Physics

contestada

The position of an object is given as a function of
time as x(t) = (3.00 m/s)t + (2.00 m/s2)t2. What is the
displacement of the object between t = 1.00 s and t
5.00 s?

Respuesta :

25-01-2022

Answer:

x(1) = 3 * 1 + 2 * 1^2 = 5 m

x(5) = 3 * 5 + 2 * 5^2 = 65 m

The displacement must be 60 m

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