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22-01-2022
Mathematics

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derivatives of cos2x+1 / sin2x ?

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IsMathFun IsMathFun

22-01-2022

Answer:

Since we know that,

cos2x= cos²x-sin²x=(cosx-sinx)(cosx+sinx)

And, sin2x=2sinx.cosx

Therefore,

1-sin2x= cos²x+sin²x-2sinx.cosx

1-sin2x= (cosx-sinx)²

Then let

y=cos2x/(1-sin2x)

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