hypotenuse=17
perpendicular=15
base=?
[tex]h^{2} = {p}^{2} + {b}^{2} [/tex]
[tex] {17}^{2} = {15}^{2} + {b}^{2} [/tex]
[tex]289 = 225 + {b}^{2} [/tex]
[tex]289 - 225 = {b}^{2} [/tex]
[tex]64 = {b}^{2} [/tex]
[tex]b = \sqrt{64} [/tex]
b=8-
Hope it helps you
make me brainliest plz
