Answer:
Step-by-step explanation:
[tex]\frac{x^{2} -x-12}{x+4} * \frac{2x^{2}-32 }{x^{2} -8x+16}[/tex] rewrite as multiplication
[tex]\frac{x^{2} +3x-4x-12}{x+4} * \frac{2(x^{2}-16) }{x^{2} -8x+16}[/tex] look to factor
[tex]\frac{x(x+3)-4(x+3)}{x+4} * \frac{2(x-4)(x+4) }{(x-4)^{2}}[/tex] , difference of 2 squares and perfect square
[tex]\frac{(x+3)(x-4)}{x+4} * \frac{2(x-4)(x+4) }{(x-4)^{2}}[/tex], finish factoring and simplify
2(x+3)
