jminklei04 jminklei04

22-06-2021
Mathematics

contestada

Solve [tex]27 = 3^4^x^+^1[/tex]

A. 1/4

B. 1/2

C. 2

D. 4

Respuesta :

wegnerkolmp2741o wegnerkolmp2741o

22-06-2021

Answer:

1/2

Step-by-step explanation:

27 = 3 ^(4x+1)

Rewriting 27 as 3^3

3^3 = 3 ^(4x+1)

Since the bases are the same, the exponents are the same

3 = 4x+1

Subtract 1

3-1 = 4x+1-1

2 =4x

Divided by 4

2/4 = 4x/4

1/2 =x

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