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  • 23-05-2021
  • Mathematics
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What is the midpoint of the x-intercepts of Ax) = (x-4)(x + 4)?​

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Аноним Аноним
  • 23-05-2021

Answer:

[tex]at \: x - intercept, \: ax) = 0 \\ (x - 4)(x + 4) = 0 \\ {x}^{2} = 16 \\ x = {}^{ + } 4 \: \: and \: \: {}^{ - } 4 \\ = > ( {}^{ + } 4, \: 0) \: and \: ( {}^{ - } 4, \: 0) \\ midpoint = ( \frac{4 - 4}{2} , \: \frac{0 + 0}{2} ) \\ midpoint = (0, \: 0)[/tex]

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