landonrivera70 landonrivera70

22-05-2021
Mathematics

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Suppose sonar on the surface of the sea locates an
object at an angle of depression of 65° and a distance
of 320 feet.
How deep is the object?

Suppose sonar on the surface of the sea locates an object at an angle of depression of 65 and a distance of 320 feet How deep is the object class=

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sqdancefan sqdancefan

22-05-2021

9514 1404 393

Answer:

290 ft

Step-by-step explanation:

The relevant trig relation is ...

Sin = Opposite/Hypotenuse

sin(65°) = d/(320 ft)

d = (320 ft)sin(65°) ≈ 290 ft

The object is about 290 feet deep.

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