Respuesta :
Answer: The balanced equation is [tex]2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}[/tex].
Explanation:
The given reaction equation is as follows.
[tex]Li + HNO_{3} \rightarrow LiNO_{3} + H_{2}[/tex]
Number of atoms present on reactant side are as follows.
- Li = 1
- H = 1
- [tex]NO_{3}[/tex] = 1
Number of atoms present on product side are as follows.
- Li = 1
- H = 2
- [tex]NO_{3}[/tex] = 1
To balance this equation, multiply Li by 2 and [tex]HNO_{3}[/tex] by 2 on reactant side. Also, multiply [tex]LiNO_{3}[/tex] by 2 on product side.
Hence, the equation can be rewritten as follows.
[tex]2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}[/tex]
Now, number of atoms present on reactant side are as follows.
- Li = 2
- H = 2
- [tex]NO_{3}[/tex] = 2
Number of atoms present on product side are as follows.
- Li = 2
- H = 2
- [tex]NO_{3}[/tex] = 2
As there are same number of atoms on both reactant and product side. Hence, the equation is now balanced.
Thus, we can conclude that the balanced equation is [tex]2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}[/tex].
