Answer: The concentration of [tex]H^{+}[/tex] ions in vinegar is 0.001 M.
Explanation:
Given: pH = 3.0
pH is the negative logarithm of concentration of hydrogen ion.
The expression for pH is as follows.
[tex]pH = - log [H^{+}][/tex]
Substitute the value into above expression as follows.
[tex]pH = - log [H^{+}]\\3.0 = - log [H^{+}]\\conc. of H^{+} = antilog (- 3.0)\\= 0.001 M[/tex]
Thus, we can conclude that the concentration of [tex]H^{+}[/tex] ions in vinegar is 0.001 M.
