rrose710
rrose710 rrose710
  • 23-04-2021
  • Mathematics
contestada

Give the equation of the circle centered at the origin and passing through the point (0,5)

Respuesta :

gugofut
gugofut gugofut
  • 23-04-2021

Answer:

[tex]x^{2} +y^{2}=25[/tex]

Step-by-step explanation

The standard equation of a circle centered at origin is  [tex]x^{2} +y^{2} =r^{2}[/tex]

r = radius of the circle

The circle is passing through the point (0,5)

∴ radius  [tex]r=\sqrt{(0-0)^{2}+(5-0)^{2} }[/tex]

               [tex]r=\sqrt{0+25}[/tex]

               [tex]r=\sqrt{25}[/tex]

               [tex]r^{2}=25[/tex]

∴ The equation of the circle is

     [tex]x^{2} +y^{2} = 25[/tex]

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