Answer:
N = 25795 loops
Explanation:
The magnetic field of a solenoid can be calculated by using the following formula:
[tex]B = \frac{\mu NI}{L}\\N = \frac{BL}{\mu I}[/tex]
where,
N = No. of loops = ?
B = Magnetic Field = 0.78 T
L = Length of solenoid = 32 cm = 0.32 m
I = Current = 7.7 A
μ = permeability of free space = 4π x 10⁻⁷ N/A²
Therefore,
[tex]N = \frac{(0.78\ T)(0.32\ m)}{(4\pi\ x\ 10^{-7}\ N/A^2)(7.7\ A)}\\[/tex]
N = 25795 loops
