l2ayrockemills l2ayrockemills
  • 25-11-2016
  • Mathematics
contestada

The radius of convergence for the power series (x-3)^2n/n from n=1 to infinity is equal to 1. What is the interval of convergence?

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Аноним Аноним
  • 27-11-2016
The solution to the problem is as follows:

|x−3|<1

X−3<1

and
−(x−3)<1

first one
X−3<1⇒x<1+3=4

for the second
−(x−3)<1⇒x−3>−1⇒x>3−1=2

thus
2<x<4

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