CInt6ainytlycamihar CInt6ainytlycamihar

21-11-2016
Mathematics

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secx-cosx/tanx=___? Explain pls ...?

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HomertheGenius HomertheGenius

24-11-2016

[tex] \frac{secx- cos x}{tan x}= \\ = \frac{ \frac{1}{cos x} -cos x}{ \frac{sinx}{cos x}}= \\ = \frac{ \frac{1-cos ^{2} x}{cos x} }{ \frac{sinx}{cos x} }= \\ = \frac{sin ^{2} x}{sin x}= [/tex]
= sin x

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