Answer:
We have the parabola as;
x^2 + 5x - 6
Step-by-step explanation:
Here, we want to get a parabola that passes through the points (1,0) and (-6,0)
The general form of a quadratic equation is;
y = ax^2 + bx + c
We have two x-intercepts at x = 1 and x = -6
A quadratic equation is expected to have two roots only and that means we have these two values as the roots
Hence, we have ;
(x-1) and (x + 6)
The parabola is thus;
(x-1)(x + 6)
= x(x + 6) -1(x + 6)
= x^2 + 6x - x -6
= x^2 + 5x - 6
